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Ivan
3 years ago
8

Match the numbers with the correct label

Mathematics
1 answer:
Firdavs [7]3 years ago
4 0

Answer:

a= -3/7

b= -0.2

c = -2/8

Step-by-step explanation:

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Try to find this answer! Thank you!
r-ruslan [8.4K]
418,200 - 326,700 = 91,500
7 0
3 years ago
What values of b satisfy 4(3b + 2)2 = 64?
Vikentia [17]
Given the equation 4(3b + 2)² = 64, dividing both sides of the equation by 4, we have (3b + 2)² = 16 and getting the square root of both sides, (3b + 2) = 4 and (3b + 2) = -4 We can solve for b for each equation and have 3b = 2 | 3b = -6 b = 2/3 | b = -2 Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
8 0
3 years ago
Fiona found 47 pens for $3.00 . Please help Fiona by figuring out the ratio. (round to 2 decimal places)
shepuryov [24]

Answer:

0.06

Step-by-step explanation:

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4 0
3 years ago
Englander equation in terms of X is correctly solved. The final step in the solution process shows that there are infinity many
Angelina_Jolie [31]
When solving a linear equation (in one variable), there are three possible outcomes: one solution, no solution, and infinitely many solutions.

You know you have one solution when you get to a situation like “x= a number”. That means that’s the only x-value that makes the equation true.

If you get to something like “2=6” which is not true, that means the equation cannot ever be made true, so there is no solution to that equation.

If you get to something like “2=2” which is always true, that means the equation is always true, no matter what value you pick for the variable. This type of equation has infinitely many solutions.

In terms of your specific question, the third answer is the one that is a true statement.
6 0
3 years ago
Thesumoftwopositivenumbersis16.whatisthesmallest possible value of the sum of their squares?
anygoal [31]
X+y=16
the sum of the squares is
x^2+y^2=sum

solve for y in first equation
x+y=16
y=16-x
subsitiute that for y in other equation

x^2+(16-x)^2=sum
x^2+x^2-32x+256=sum
2x^2-32x+256=sum
take derivitive to find the minimum value (or just find the vertex because the parabola opens up)
derivitive is
4x-32=derivitve of sum
the max/min is where the derivitive equals 0
4x-32=0
4x=32
x=8

at x=8
so then y=16-8=8

the smallest value then is 8^2+8^2=64+64=128
5 0
4 years ago
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