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Vsevolod [243]
3 years ago
14

This week, conrad will work 1 3/4 times as long as last week. giovanni will work 1 1/3 times as long as last week. sally will wo

rk 2/3 the number of hours she worked last week. match each employees name to the number of hours he or she will work this week ?
Mathematics
2 answers:
quester [9]3 years ago
8 0
Hi, thank you for posting your question here at Brainly.

This question could easily be solved if we knew the time each of them work last week. For educational purposes, let's assume it took each of them 8 hours last week. Then,

Conrad: (1+3/4)(8) = 14 hours
Giovanni: (1+1/3)(8) = 10.7 hours
Sally: (2/3)(8) = 5.3 hours
sweet [91]3 years ago
6 0

Answer:

Step-by-step explanation:

Conrad work 6 2/3 hours

Giovanni work 9 1/2 hours

Sally work 10 3/4

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A cube has a volume of 3375 cubic units calculate the length of one side of the cube
8090 [49]

Answer:

volume = length^3

3375= length^3

therefore length = 15 units

3 0
1 year ago
Will mark BRAINLIEST! PLEASE HELP!
yulyashka [42]

Answer:

3 bob's burger= 23.67

2 starry night= 17.98

4 clear= 42

Step-by-step explanation:

3 x 7.89= 23.67

2 x 8.99= 17.98

4 x 10.50= 42

6 0
3 years ago
Ethan Doran is a physical therapist. His biweekly salary is $3,985. What is his annual salary? (Hint: You need to know how many
Furkat [3]
If you are paid bi-weekly, you will receive 26 checks a year.


$3,985x26=$103,610

Ethan Doran’s annual salary is $103,610.
6 0
3 years ago
Read 2 more answers
Consider the following hypothesis test:
Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

H_0: \mu\leq50\\\\H_a:\mu> 50

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0
3 years ago
The demand function for a product is modeled by p = 400 − 4x, 0 ≤ x ≤ 100, where p is the price per unit (in dollars) and x is t
lawyer [7]

Answer:

Demand is Elastic when Price > 200 ; Demand is inelastic when Price < 200

Step-by-step explanation:

p = 400 - 4x

4x = 400 - p

x = (400 - p) / 4 → x = 100 - p/4

Elasticity of demand  [ P ed ] = (Δx / Δp) x (p / x)

Δx / Δp  [Differentiating x w.r.t p]  = 0 - 1/4  → = -1/4

P ed =  <u>-1</u> x<u> p </u>

            4   (400 - p)/4

= <u>-1</u> x <u> 4p </u>              = -p / (400-p)

  4   (400 - p)

Price Elasticity of demand : only magnitude is considered, negative sign is ignored (due to negative price demand relationship as per law of demand).

So, Ped = p / (400 - p)

Demand is Elastic when P.ed > 1

p / (400-p)  > 1

p > 400 - p

p + p > 400  → 2p > 400

p > 400 / 2 →  p > 200

Demand is inelastic when P.ed < 1

p / (400-p)  < 1

p < 400 - p

p + p < 400  → 2p < 400

p < 400 / 2 →  p < 200

4 0
3 years ago
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