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3 years ago

Compound events help please!!!’

Mathematics

1 answer:

julsineya [31]3 years ago

8 0

Im going to guess its 5/12. i havent learnt this but check my working. so the chances of getting multiple of 3 on first roll is 2/6 = 1/3. the posibility of getting total of 8 on both rolls is 5/6×1/6 = 5/36. so 5/36÷1/3=5/12? im really not very sure on this

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PLS PLS PLS HELP ME WITH THIS QUESTION!!!!!!!

Artemon [7]

Answer:

f. 260 in by 100 in

Step-by-step explanation:

13 + 5 = 18

720/18 = 40

Find length:

40*13 = 520

520/2 = 260 <-- must divide by 2, 520 is the sum of twice the length

Find width:

40*5 = 200

200/2 = 100 <-- must divide by 2, 200 is the sum of twice the width

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3 years ago

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Please answer this correctly without making mistakes

Mamont248 [21]

Answer:

99g

Step-by-step explanation:

I'm guessing on this one but maybe because a whole number has no remainder

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3 years ago

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20 POINTS

RUDIKE [14]

<em>The correct expressions are as follows:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}$

$\texttt{ }$

<em>From the results above, it can be concluded that the correct statements are:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

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4 years ago

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Find the total amount you will pay given an original price of $24.99 and tax rate of 5%.

Solnce55 [7]

Answer:The answer is 15.78

Step-by-step explanation:

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3 years ago

R+q-r; use q=6,and r=2

Anastasy [175]

Answer:

so you would replace all r with 2 which is 2+q-2

then replace the q with 6 so it would be: r+6-r

combined both of these to get

2+6-2

which would equal to 6

add the 2 and the 6 to get 8

then subtract 2 to get 6

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3 years ago

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