Calculate δe, if q= 0.764 kj and w= -830 j . express your answer using two significant figures.
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Answer:
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 21.6 - 0.3 = $21.3.
The upper end of the interval is the sample mean added to M. So it is 21.6 + 0.3 = $21.9.
The 80% confidence interval for the mean per capita income in thousands of dollars is between $21.3 and $21.9.