Answer:
(x-2)²+(y-4)² = 25
Step-by-step explanation:
Standard equation of a circle is expressed as
(x-a)²+(y-b)² = r²
Center = (a, b)
Radius = r
Get the radius
r² =(0-4)²+(-1-2)²
r² = (-4)²+(-3)²
r² = 16 + 9
r² = 25
Centre = (2, 4)
Substitute into the equation
(x-2)²+(y-4)² = 25
This gives the required equation
Using the SA formula you'll have to substitute in the edge length for s.
SA = 6(312)²
SA = 584064
The surface area is 584,064 feet²
Hope this helps :)
Answer:
Step-by-step explanation:
When you are changing a repeating decimal to a fraction, there is a trick you have to know. 2 actually. Put the decimal right before the repeating starts and right after the repeating starts. This one is a bit tricky since the decimal is after a 1, and 1 is what is repeating. So let's leave that one as is and simply say that
x = -1.11111
Now let's move the decimal right after the second one. To do that you have to multiply by 10. So we then can say that
10x = -11.11111
For this problem, we will disregard the negative til the end because it just makes things confusing.
Subtract the smaller equation from the larger:
10x = 11.111111
- 1x = 1.111111
and get
9x = 10
Divide both sides by 9 to get 10/9 which is 1 1/9 as a mixed fraction. Let's check it first to see if we're correct, then we'll throw the negative sign back on.
10/9 on your calculator gives you 1.111111111 repeating, so now that we know we are correct, the mixed fraction is
-1 1/9
Answer:
Part a) The inequality that represent the situation is
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
Divide by 10 both sides
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to