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3 years ago

PLEASE HELP!!

Mathematics

1 answer:

Vikentia [17]3 years ago

4 0

Answer:

Part a) The inequality that represent the situation is

$x+(3x)+(6x) \leq 350\ in$

Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to $35\ inches$

Step-by-step explanation:

Let

x------> the length of the first wire

3x---> the length of the second wire

2(3x)=6x -----> the length of the third wire

Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION

we know that

The inequality that represent the situation is

$x+(3x)+(6x) \leq 350$

Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?

we know that

The shortest piece of wire is the first wire

Solve the inequality

$x+(3x)+(6x) \leq 350$

$10x \leq 350$

Divide by 10 both sides

$x \leq 35\ in$

The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to $35\ inches$

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