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Stels [109]
3 years ago
15

Please answer this sample space question.

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

I think the answer is c 24

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Alyssa is building a brick mailbox. She is going to stack bricks that are each \dfrac23 \text{ft}
aalyn [17]
Given that each of the brick is \frac{2}{3} ft tall and the finished stack of bricks is 4\frac{2}{3} ft tall.

Let the number of bricks in the stack be x, then

\frac{2}{3} x=4 \frac{2}{3} = \frac{14}{3}  \\  \\ \Rightarrow x= \frac{ \frac{14}{3} }{ \frac{2}{3} } = \frac{14}{3} \times \frac{3}{2}  \\  \\ = \frac{14}{2} =7

Therefore, 7 bricks will go in the stack.
3 0
3 years ago
Tonya saved 564$ in one year if she saved the same amount each month how much did Tony's save in two months
Dvinal [7]
$94 in 2 months
you take 564 and divide it by 12 for 12 months in a year and get 47. then you add 47 and 47 for 2 months and get 94
7 0
3 years ago
Jaime en un joven que vive en puyo con su padre. A jaime le gusta cosechar chonta con su padre los sabados en la mañana jaime ha
xenn [34]

Answer:

\large \boxed{\text{23 s}}

Step-by-step explanation:

Jaime is at point A and wants to get across the river to Point B.

They must head upstream towards Point C.

1. Calculate the net speed across the river.

∆ABC is a right triangle, so

\begin{array}{rcl}AB^{2} + BC^{2} & = & AC^{2} \\AB^{2} +10^{2} & = & 12^{2} \\AB^{2}+100& = & 144 \\AB^{2}& = & 44\\AB & = & \sqrt{44}\\& = & 2\sqrt{11}\\& \approx &\textbf{6.633 m/s}\\\end{array}

2. Calculate the time to cross the river

\text{Time} = \text{150 m} \times \dfrac{\text{1 s}}{\text{6.633 m}} \approx \textbf{23 s}\\\\\text{It will take $\large \boxed{\textbf{23 s}}$ to cross the river.}

7 0
3 years ago
Can you please help me with this i don’t understand
Alinara [238K]

Answer:

  (5, 2)

Step-by-step explanation:

<h3>understanding the question</h3>

The question is asking you to express the temperature at 5 pm as a pair of graph coordinates.

Doing this requires that you ...

  • read from the graph the temperature at 2 pm
  • read from the graph the temperature at 8 pm
  • figure the temperature halfway between those values
  • express the 5 pm temperature as an ordered pair (hours, °C)

__

<h3>reading the graph</h3>

The description of the graph tells you the horizontal scale is hours after noon, so the temperature at 2 pm will be a point on the graph with an x-coordinate of 2. That point is (2, 7), indicating the temperature at 2 pm is 7 °C.

Likewise, the temperature at 8 pm is shown as the point on the graph with x-coordinate 8. That point is (8, -3), indicating a temperature of -3°C at 8 pm.

<h3>halfway temperature</h3>

The temperature halfway between those values (7 °C and -3 °C) can be found several ways. Perhaps the easiest is to average the values:

  (7 +(-3))/2 = 4/2 = 2

The temperature at 5 pm is 2 °C.

<h3>coordinates</h3>

Coordinates on the graph are ordered pairs of the form (x, y) = (hours, °C). The time 5 pm is 5 hours after noon, so the x-coordinate is 5. The temperature at 5 pm is halfway between the temperatures at 2 and 8 pm, which we have computed to be 2 °C, so the y-coordinate is 2.

The coordinates that represent the temperature at 5 pm are ...

  (5, 2)

6 0
2 years ago
This is for the real ones- find the missing side x. Giving brainliest.
Luba_88 [7]

Answer: The answer is X equals 10 2/3.

Explanation: This is a proportion. We see that the right rectangle when turned to the right is proportional to the left rectangle. On the left rectangle, the smaller side is 6 ft, and the larger side is 16 ft. On the right rectangle, the smaller side is 4 ft. 6 ÷ 1.5 = 4, therefore 16 ÷ 1.5 = 10 2/3.

7 0
2 years ago
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