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alisha [4.7K]
3 years ago
7

Sue sold 26 more newspapers than bill, and bill sold three times as many as Harry. If Harry sold p newspapers, how many did Sue

sell?
Mathematics
1 answer:
alexdok [17]3 years ago
7 0

Answer:

3p + 26  

Step-by-step explanation:

Let S = Sue's newspapers sold

     B = Bill's newspapers sold

     H = Harry's newspapers sold.

We have three conditions:

(1)   S = B + 26

(2)  B = 3H

(3)  H = p     Substitute (3) into (2)

(4) B = 3p     Substitute (4) into (1)

      S = 3p + 26

Sue sold 3p + 26 newspapers.

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Find the area of the region enclosed by the graphs of the functions
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Answer:

\displaystyle A = \frac{8}{21}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  4. Multiplication
  5. Division
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  • Multiplication Property of Equality
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<u>Algebra I</u>

  • Terms/Coefficients
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  • Graphing
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<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]:                                                                 \displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Property [Addition/Subtraction]:                                                          \displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx

Area of a Region Formula:                                                                                     \displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

  1. Substitute in variables [Area of a Region Formula]:                                     \displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx
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Topic: AP Calculus AB/BC (Calculus I/II)  

Unit: Area Under the Curve - Area of a Region (Integration)  

Book: College Calculus 10e

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