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Alex Ar [27]
3 years ago
12

What is the length of the the midsegment of a trapezoid with bases of length 14 and 24​?

Mathematics
2 answers:
krek1111 [17]3 years ago
6 0

Step-by-step explanation:

Length \: of \: midsegment \\  =  \frac{1}{2}  \times sum \: of \: lengths \: of \: bases \\  \\  = \frac{1}{2}  \times(14 + 24) \\  \\  = \frac{1}{2}  \times38 \\  \\  = 19  \: units

lesya [120]3 years ago
5 0

Answer:19

Step-by-step explanation:The midsegment of a trapezoid connects the midpoints of the two congruent sides of the trapezoid, and is parallel to the pair of parallel sides.Therefore , to find the length of the midsegment , all we need do is to add the two bases together and divide by two , that is :

Length of mid segment = \frac{14+24}{2}

Length of mid segment = \frac{38}{2}

Length of mid segment = 19

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Answer:

725.7

Step-by-step explanation:

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3 years ago
John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches
ikadub [295]

a) The probability  that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is  0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show  = 0.7   ⇒ P(J) = 0.7

Probability that Jane watches a certain show  = 0.3   ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

 = 0.4   ⇒ P(J/Je) = 0.4

a. )  Here, we need to find the probability of  both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

P(J/Je)  = \frac{P(J \cap Je)}{P(Je)}

\implies  0.4  = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3  = 0.12

Hence the probability  that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

P(Je/J)  = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J)  = \frac{0.12}{0.7}  = 0.1714

Hence, the probability that Jane watches the show, given that John does is  0.1714.

c) As we can see P(Jane ∩ John) =  0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12  = 0.88

7 0
3 years ago
Help please 60 points and brainiest!!
lakkis [162]

Answer:

The conclusion is that the robber is fast.

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3 0
3 years ago
Read 2 more answers
PLISS ANSWER :C DONT ANSWER IF YDK THAnKSSS<br> *also pls look at both images :)*
Iteru [2.4K]

Answer:

First image: (6, -1)

2nd image: y = 63

Explanation:

1)

2x + y = 11

1/2x - 5y = 8

y = -2x + 11

1/2x - 5(-2x + 11) = 8

1/2x + 10x - 55 = 8

10.5x - 55 = 8

10.5x = 63

x = 6

2x + y = 11

2(6) + y = 11

12 + y = 11

y = -1

(x , y) = (6, -1)

2)

1/4(8y - 4.8) = 2 (0.9y + 5.4) + 3/5

2y - 1.2 = 1.8y + 10.8 + 0.6

0.2y - 1.2 = 11.4

0.2y = 12.6

y = 63

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3 years ago
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Hope this answer helps you! If it did, please mark it as the brainiest! I would really appreciate it! :)

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