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makkiz [27]
4 years ago
13

Please Answer!!!

Mathematics
1 answer:
gavmur [86]4 years ago
8 0
This is the answer, attached below. :)

You might be interested in
Help please! really appreciate it
arlik [135]

Answer:

x=26

Step-by-step explanation:

exterior angles theorem meaning they're equal to each other.

5x+7=8x-71

add 71 to 7

5x+78=8x

subtract 5x from 8x

78=3x

divide 78 and 3

x=26

to check your work plug 26 into each equation:

5(26)+7= 137°

8(26)-71= 137°

because they're the same you know that x must equal 26

hope this helps!❤

4 0
4 years ago
Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
A snack-size bag of M&Ms candies contains 14 red candies, 10 blue, 5 green, 11 brown, 3 orange, and 12 yellow. If a candy is
Nitella [24]

Answer:

The odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

Step-by-step explanation:

Red candies = 14

Blue candies = 10

Green candies =  5

Brown candies = 11

Orange candies = 3

Yellow candies = 12

Total No. of candies = 14+10+5+11+3+12 = 55

(a) the odds of getting a green M&M

Green candies = 5

Total number of candies excluding green or unfavorable = 50

Odds of getting a green M&M  = \frac{\text{favorable outcome}}{\text{Unfavorable outcomes}}

                                                   = \frac{5}{50}

                                                   = \frac{1}{10}

(b) the probability of getting a green M&M

Green candies = 5

Total No. of candies = 55

So,  the probability of getting a green M&M =\frac{5}{55}

                                                                        =\frac{1}{11}

Hence the odds of getting a green M&M  is \frac{1}{10} and  the probability of getting a green M&M  is \frac{1}{11}

4 0
3 years ago
Which figure represents the image of parallelogram LMNP after a reflection across the line y = x?
Taya2010 [7]
When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. This gives you such reflection rule:

From the diagram:
L(3,1), M(4,3), N(5,3) and P(4,1).
Using the reflection rule, you can find coordinates of image points:
L'(1,3), M'(3,4), N'(3,5) and P'(1,4).
As you can see, these are coordinates of vertices of the figure C.
Answer: correct choice is option 3 - figure C.
7 0
3 years ago
What is the property of -10+3 = 3+(-10)
maxonik [38]

Answer: −7 = −7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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