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4 years ago

What is the least common denominator of 1/9 and 2/3

Mathematics

1 answer:

Kipish [7]4 years ago

8 0

Answer:

Step-by-step explanation:

All u have to do is think only about two denominators, 9 and 3

And then memorize the multiplication of any number out of these two, until u get a number which is divisible by the other number. Its like,

9×1= 9

is it divisible by 3?

9/3= 3

Oh yes, it is divisible by 3 with no remainings. So that is the least common denominator

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Determine whether 2/15 is closest to 0,1/2 or 1

stira [4]

Since 15ths are smaller pieces 2 of 15 would'nt even really be close to 1/2 half of 15 is 7.5 so not even close. or 1 so the answer would be that it is closer to 0. Hope it helps!!

7 0

4 years ago

If a 12-sided regular polygon rotates about its center, at which angle of rotation will the image of the polygon coincide with t

Snowcat [4.5K]

Central angle of a regular polygon:
Ф = 360° : n.
If n=12: Ф = 360° : 12 = 30°
At the angle of rotation Ф = 30° the image of the polygon will coincide with the preimage.

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3 years ago

Which is the solution to the inequality? One-fourth + x less-than StartFraction 5 over 6 EndFraction x less-than StartFraction 7

Natalka [10]

Answer

it is c

Step-by-step explanation:

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3 years ago

Read 2 more answers

T-shirts at a clothing store cost $19 each Rory bought several T-shirts at this price and paid $57 how many t-shirts did Rory bu

Vitek1552 [10]

One t-shirt = $19

Number of t-shirts = $57 ÷ $19 = 3

Answer: 3 t-shirts

4 0

3 years ago

Read 2 more answers

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

3 0

3 years ago