Write an equation for the description. Two-thirds a number x plus 4 is 6.

How can i factorise <img src="https://tex.z-dn.net/?f=12x%20-%206" id="TexFormula1" title="12x - 6" alt="12x - 6" align="absmidd

Lorico [155]

Answer:

6(2x - 1)

Step-by-step explanation:

Given

12x - 6 ← factor out common factor of 6 from both terms

= 6(2x - 1) ← in factored form

8 0

3 years ago

Read 2 more answers

Simplify 9 to the power of 2 over 9 to the power of 7 please help someone quick!

Charra [1.4K]

Answer:

1/59049

Step-by-step explanation:

4 0

3 years ago

2.3.2: Michael Myers predicts that SAT scores predict college graduation rates in a linear fashion. U of M has an average SAT of

AleksAgata [21]

Answer:

$y = \frac{5000r}{3} -50$

Step-by-step explanation:

Represent the SAT score with y and the rate with r.

So, we have:

$(r_1,y_1) = (90\%,1450)$

$(r_2,y_2) = (69.6\%,1110)$

Required

Determine the equation in slope intercept form

First, we calculate the slope

$m =\frac{y_2 - y_1}{r_2 - r_1}$

This gives:

$m =\frac{1110 - 1450}{69.6\% - 90\%}$

$m =\frac{-340}{-20.4\%}$

Convert percentage to decimal

$m =\frac{-340}{-0.204}$

$m =\frac{340}{0.204}$

Multiply by 1000/1000

$m =\frac{340*1000}{0.204*1000}$

$m =\frac{340000}{204}$

$m = \frac{5000}{3}$

The equation is then calculated as:

$y - y_1 = m(r - r_1)$

This gives:

$y - 1450 = \frac{5000}{3}(r - 90\%)$

Open Bracket

$y - 1450 = \frac{5000r}{3} - \frac{5000}{3}*90\%$

Convert percentage to decimal

$y - 1450 = \frac{5000r}{3} - \frac{5000}{3}*0.90$

$y - 1450 = \frac{5000r}{3} - 5000*0.30$

$y - 1450 = \frac{5000r}{3} - 1500$

Make y the subject

$y = \frac{5000r}{3} - 1500+1450$

$y = \frac{5000r}{3} -50$

3 0

2 years ago

In the above sketch the measure of angle a is how many degrees.

Yuliya22 [10]

It is also 50 degrees

7 0

3 years ago

WILL GIVE BRAINLIEST AND 25 POINTS! Which of the following statements are true? Check all that apply. A. If any row of a square

sertanlavr [38]

Answer:

Option A, B and E

Step-by-step explanation:

Determinant = ad-bc

Let's look at the picture and solve all

Option A)

If the row ( c and d ) is zero, the determinant will be zero

=> a(0)-b(0)

=> 0-0

=> 0 (So, True)

Option B)

If a = b = c = d (Let's say 1), the determinant will be

=> (1)(1)-(1)(1)

=> 1-1

=> 0 (So, True)

Option C)

An Identity matrix is

=> $\left[\begin{array}{ccc}1&0\\0&1\end{array}\right]$

So , it's determinant will be

=> (1)(1)-(0)(0)

=> 1-0

=> 1 (So, False)

Option D)

The determinant with matrix will all positive numbers can be negative as well as positive. This is not necessary that it would be positive. (So, False)

Option E)

A zero matrix is

=> $\left[\begin{array}{ccc}0&0\\0&0\end{array}\right]$

So, it's determinant is:

=> (0)(0)-(0)(0)

=> 0-0

=> 0 (So,True)

5 0

3 years ago