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oksian1 [2.3K]
3 years ago
13

Find an equation of the line containing the given pair of points. (-3,0) (0,2)

Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

y = 2/3x + 2

Step-by-step explanation:

image attached

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WILL MARK BRAINLYIST
rodikova [14]

Answer:

D = 45 and C = 26

Step-by-step explanation:

The bigger triangle has a 90 degree corner add that to 64 and you will get 164 (all of the triangles angles have to add to 180) from 180 subtract 164 and you get 26 which is C's answer

For D just divide 90 by 2 (90/2)=45

7 0
3 years ago
X^2 + 7x – 18 = 0<br> a<br> {–2, 9}<br> b<br> {–9, 2}<br> c<br> {2, 9}<br> d<br> {–2, –9}
Sedaia [141]

Answer:

b)-9,2

Step-by-step explanation:

x^2+7x-18=0

x^2+9x-2x-18=0

x(x+9)-2(x+9)=0

(x+9)(x-2)=0

therefore

x=-9

x=2

6 0
3 years ago
Trying to get my grade up
GalinKa [24]

Answer:

when x = 0, the answer is 0

when x = 3, the answer is 24

when x = 4, the answer is 32

7 0
3 years ago
Read 2 more answers
What is the equation of this graph? It is a cosine needing something along the lines of y=acos(b(x-c))+d
Sholpan [36]
Jesus Christ is the only true source of joy
6 0
3 years ago
CITY |. Temperature (°F) St. Louis | 32 Montreal |. -18 Buffalo. | -8 Orlando. |. 68 Juneau. |. -26 By noon, the temperature In
Leno4ka [110]

Answer:

6°F

58°F

Step-by-step explanation:

From the data Given :

Temperature rise in Buffalo by noon time = 14°F

The initial temperature at Buffalo = - 8°F

Rise in temperature = 14°F

Therefore, temperature at noon = (-8 + 14)°F = 6°F

B.)

Temperature at 6am in St. Louis = 32°F

Temperature at 6am in Juneau = - 26°F

Temperature difference :

(32 - (-26))°F

32 + 26

= 58°F

Temperature in St. Louis is 58°F higher

8 0
3 years ago
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