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oksian1 [2.3K]
3 years ago
13

Find an equation of the line containing the given pair of points. (-3,0) (0,2)

Mathematics
1 answer:
Shkiper50 [21]3 years ago
4 0

Answer:

y = 2/3x + 2

Step-by-step explanation:

image attached

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How much higher is 500 than -400 m
gogolik [260]

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900m

Step-by-step explanation:

All you have to do is find the difference between the two measurements

500 - (-400)

Then, two negatives create a positive:

500 + 400

= 900

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A chestnut falls from a tree 45 feet above ground.Use the vertical motion model to find how long it takes to hit the ground.Roun
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How do you describe the square root of a rational number​
lisabon 2012 [21]

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I am a 4th grader I don't know

Step-by-step explanation:

4 0
2 years ago
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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
Explain why 2a+3b=5ab
Ahat [919]

That's not correct. The terms 2a and 3b are not like terms, so we cannot combine them to get 5ab. We simply leave it as 2a+3b.

If you had 2a+3a, then it would simplify to 5a

Similarly, 2b+3b = 5b

Or you could have 2ab+3ab = 5ab

The key is that the variable portions must match up to be able to add them.

8 0
3 years ago
Read 2 more answers
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