The volume of the cone is 3.14 x 14 x 14
We are given with a bag containing 13 dark chocolates, 16 white chocolates, and 11 milk chocolates. hence the sample space is 13 + 16 + 11 equal to 40 chocolates. The <span> probability that she randomly picks a white chocolate is 16/40 or 2/5 and that she picks a milk chocolate is 11/40. Hence the probability of picking either is (16+11) /40 equal to 27/40</span>
Answer:
the third option - they are perpendicular to each other.
Step-by-step explanation:
for a perpendicular slope we need to exchange the x and y values (remember, a slope is the ratio of y/x) and flip the sign.
and that is exactly what happened here.
Given that there is no any option to choose I am going to help you according to the concepts of
Congruent Triangles. Two triangles are congruent if and only if:
1. They have:exactly the same three sides
2. exactly the same three angles.
<span>There are five ways to find if two triangles are congruent but in this problem we will use only two.
First Answer:<u>ASA criterion:</u> </span><em>A</em><span><em>ngle, side, angle</em>. This means that we have two triangles where we know two angles and the included side are equal.</span>
So:
If ∠BAC = ∠DEF and

<em>Then ΔABC and ΔEFD are congruent by ASA criterion.</em>
Second answer:<u>SAS criterion:</u> <em>S</em><span><em>ide, angle, side</em>. This means that we have two triangles where we know two sides and the included angle are equal.
</span>

<em>Then ΔABC and ΔEFD are congruent by SAS criterion.</em>
14n=-126
/14 /14 divide by 14 on both sides of the
equation
n=-9