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3 years ago

Which is a correct classification for the triangle?

Mathematics

1 answer:

Mkey [24]3 years ago

3 0

The third angle is 180 - 53 - 27 = 100o
That angle is greater than 90o

The triangle is obtuse
B<<<<===== answer

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Triangles L M N and L K N are connected at side L N. A line is drawn from point M to point K and intersects side L N at point P.

lesya692 [45]

The true statement is Line MK is the perpendicular bisector of LN and ML is ≅ MN.

<h3>What is perpendicular?</h3>

Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Given:

Δ LMN and Δ LKN are connected at side LN.

As per the information,

Line MK is the perpendicular bisector of LN. and ML ≅ MN.

Learn ore about this concept here:

brainly.com/question/25397944

#SPJ1

8 0

1 year ago

Mr.Martinez rents a car for one day.The charge is $36 plus $0.18 per mile.Mr.Martinez has a budget $60.How many miles can he dri

kondor19780726 [428]

1... the wording is a little confusing.
Is the charge $0.18 per mile or is it actually $36.18 per mile?

8 0

3 years ago

PLEASE ANSWER THIS QUESTION

AleksAgata [21]

The answer is 135 cubes.

3 0

2 years ago

How do you find a solution for an inequality equation?

kozerog [31]

Answer: By adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own. Don't multiply or divide by a variable unless you know it is always positive or always negative.

Step-by-step explanation:

5 0

3 years ago

Given right triangle MNL what is the value of cos(M)?

FromTheMoon [43]

Step $1$

<u>Find the length of the side MN</u>

we know that

Applying the Pythagorean Theorem

$ML^{2} =NL^{2} +MN^{2}$

Solve for MN

$MN^{2}=ML^{2} -NL^{2}$

in this problem

$ML=25\ units\\ NL=15\ units$

Substitute in the formula above

$MN^{2}=25^{2} -15^{2}$

$MN^{2}=400$

$MN=20\ units$

Step $2$

<u>Find the value of cos (M)</u>

we know that

in the right triangle MNL

$cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}$

$adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units$

Substitute

$cos (M)=\frac{20}{25}$

$cos (M)=\frac{4}{5}$

$cos (M)=0.8$

therefore

The answer is

The value of cos(M) is equal to $0.8$

6 0

3 years ago