The initial value of the linear relationship is 5.
Solution:
- The y-intercept is the point where the line crosses at y-axis.
- The initial value of the linear function is the y-intercept.
On observing the graph, the line crosses y-axis at the point (0, 5).
So, y-intercept = 5
That is initial value = 5
Therefore the initial value of the linear relationship is 5.
Answer:
part 1) 0.78 seconds
part 2) 1.74 seconds
Step-by-step explanation:
step 1
At about what time did the ball reach the maximum?
Let
h ----> the height of a ball in feet
t ---> the time in seconds
we have

This is a vertical parabola open downward (the leading coefficient is negative)
The vertex represent a maximum
so
The x-coordinate of the vertex represent the time when the ball reach the maximum
Find the vertex
Convert the equation in vertex form
Factor -16

Complete the square


Rewrite as perfect squares

The vertex is the point 
therefore
The time when the ball reach the maximum is 25/32 sec or 0.78 sec
step 2
At about what time did the ball reach the minimum?
we know that
The ball reach the minimum when the the ball reach the ground (h=0)
For h=0



square root both sides


the positive value is

Answer:
4 dollars for 2 drinks (2 dollars for 1 drink)
Step-by-step explanation:
Okay, so you can get 3 snapple drinks from 6 dollars. and you want to know the cost of 2 snapple drinks.
3 ÷ 6 = 2
So 1 drink is 2 dollars, if you wanted to buy 2 drinks the cost would be 4 dollars! Have a great day friend! :D
Answer:
Sure
Step-by-step explanation:
Answer:
2.
A. (P+h)(x)
2x/x+4 (x-1) + x/x-1 (x+4)
2x^2-1/x^2-4
+
X^2+4/x^2-4
= 3x^2+3/x^2-4
B. (F-g)(x)
X^2-7x+6-x - 6
= x^2 -8x
C. (Fg)(x)
(X^2-7x+6)(x-6)
= x^3-13x^2+48x-36
D. (H/p)(x)
X/x-1 / 2x/x+4
X/x-1 / x+4/2x
= X^2+4x/2x^2-2x
3.
A. (F+g)(3)
X^2+1 + x-4
3^2+1 + 3-4
10 -1
= 9
B. (f-g)(0)
X^2+1 - x-4
0+1 -0-4
1-4
= -3
C. (Fg)(-k)
(X^2+1) (x-4)
(-k^2+1) (-k-4)
K^3+4k^2-k-4
D. (F/g)(k-2)
X^2+1 /x-4
K-2^2+1 / k-2 -2
= K^2-4k+5 / k-4
Step-by-step explanation: