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Zolol [24]
3 years ago
11

Please help with this ill mark brainlyess answer if its right

Mathematics
2 answers:
geniusboy [140]3 years ago
4 0
30 is 20% of 150.

30/x = 20/100

30 * 100 = 20 * x

(30 * 100)/20 = x

x = 150
Aleks04 [339]3 years ago
4 0
I think your answer is 

150

Glad I could help, and good luck!

AnonymousGiantsFan
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Need help please!!!! Brainiest if answered correctly!!!! No link, it will be reported!!
patriot [66]
The mean increases. When Deleware (2,000: 2) is included the mean must be divided by 9 instead of 8.
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2 years ago
How do you find both lengths of the diagonals of a rhombus?
attashe74 [19]
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statuscvo [17]

Answer:

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Step-by-step explanation:

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4 0
2 years ago
g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected
Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

np=50*0.78=39  \geq 10

n(1-p)=50*(1-0.78)=11 \geq 10

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}})

With the following parameters:

\mu_ p = 0.78

\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586

6 0
3 years ago
What is the last one number 12
rosijanka [135]
What is the last one number 12
8 0
2 years ago
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