Oh my. ALEKS brings back terrible memories, but I hope you managed to do this. You should’ve drawn a line splitting the angle perfect in two. I’m not exactly certain how to use the tool as I’ve never really gotten to to that topic, but I hope you did well. :)
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
1) cf= 24 hours/1 day, 1 hour/60 minutes
30 x 1/60 = .5
10 x 24/1 = 240
240 + .5 = 240.5 hours
2) cf = 24 hours/1 day, 60 minutes/1 hour, 12 inches/1 foot
a) 0.6 x 12/1 = 7.2 inches
b) 7.2 x 1/24 = 0.3 inches per hour
Answer:
d
Step-by-step explanation:
<33
Answer:
just add or * them to get the answer
Step-by-step explanation:
