The simplest way of writing this:
<span><span><span><span>7p</span>−1</span>−<span>9p</span></span>+5</span><span>=<span><span><span><span><span><span>7p</span>+</span>−1</span>+</span>−<span>9p</span></span>+5</span></span>Combine Like Terms:<span>=<span><span><span><span>7p</span>+<span>−1</span></span>+<span>−<span>9p</span></span></span>+5</span></span><span>=<span><span>(<span><span>7p</span>+<span>−<span>9p</span></span></span>)</span>+<span>(<span><span>−1</span>+5</span>)</span></span></span><span>=<span><span>−<span>2p</span></span>+4</span></span>Answer:<span>=<span><span>−<span>2p</span></span>+<span>4</span></span></span>
Answer:
Y=3x+3
The y intercept is 3 and use rise over run to find m.
Given:
There is a ratio given as 16:9 of width to height and diagonal is 27 iniches
Required:
We need to find the value of height
Explanation:
By ratio
where w is width and h is height
by using pythagorean theorem
to find h
Final answer:
height is 13.24 inches
Answer:
1.) 120 mph
2.) 30 mph
Step-by-step explanation:
Given that a man flies a small airplane from Fargo to Bismarck, North Dakota- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1.2 hours. What is the planes speed in still air, and how fast is the wind blowing?
Let the wind speed = w
and the plane speed = p
From the first sentence,
P - w = 180/ 2
P - w = 90 ....... ( 1 )
From the second statement,
P + w = 180/1.2
P+ w = 150 ...... ( 2 )
Solve equation 1 and 2 simultaneously
P + w = 150
P - w = 90
Add the two equations
2P = 240
P = 120 mph
Substitute p in equation 1
W = 150 - 120
W = 30
Therefore, the wind speed is 30 mph and the plane speed is 120 mph
Answer:
Step-by-step explanation:
The function sin(x) adopts the value -1 for x = .
That is when the segment pictured in red in the attached image is pointing from the center of the circle down. Recall that the sin function gives us the y-readout of the free end of the rotating segment in the unit circle.
