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3 years ago

If point C is between points A and B, then __+CB = AB.

Mathematics

2 answers:

NARA [144]3 years ago

7 0

AC, the sum of the points AC+CB=AB

vazorg [7]3 years ago

3 0

AC. AC+CB=AB
Think of a line which has endpoints A and B with C as the midpoint.

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Please help and it will be great if someone explain this :p

In-s [12.5K]

To find slope use the formula rise over run. Rise up from 0 to 16 then run from 0 to 2 to get rise of 16 and run of 2 (16/2). Simplify the fraction 16/2=8 (like a regular division problem) and that give you your slope. The y-intercept is 0 because the line touches the y axis (the vertical axis) at 0 :)

8 0

3 years ago

Read 2 more answers

The area of a rectangular pool is given by the trinomial 2y^2-y-3. What are the possible dimensions of the pool? Use factoring.

RSB [31]

Answer:

(2y−3)(y+1) hope this helps!

7 0

3 years ago

Describe and correct the error. x + 4 > 13

butalik [34]

Answer:

x=10

Step-by-step explanation:

13-4=9

For it to be bigger than 13, it has to be one more than 9 which is 10.

6 0

4 years ago

A certain brand of electric bulbs has an average life of 300 hours with a standard deviation of 45. A random sample of 100 bulbs

tigry1 [53]

Answer:

$P(\bar{x}$

Step-by-step explanation:

Average life of electric bulbs = 300 hrs

standard deviation = 45

Total no of bulbs tested = 100

Probability that sample mean is less than 295 =?

Using Central Limit Theorem

$P(\bar{x}$

From table of normal distribution:

$P(\bar{x}$

3 0

3 years ago

Read 2 more answers

Find the value of x Use sin, cos, or tan

Shalnov [3]

Answer:

58.896º

Step-by-step explanation:

In this problem, we are given the angle 23º, as well as it's opposite and adjacent sides as 25 and x respectively.

According to SOHCAHTOA, we should use tan to solve for x, because we already know the opposite and adjacent sides. Let's set up the equation:

$\tan=\frac{opposite}{adjacent} \\\\\tan(23\textdegree)=\frac{25}{x} \\\\x=\frac{25}{\tan(23\textdegree)}\\\\x \approx 58.896\textdegree$

I hope this helps! Let me know if you have any questions :)

5 0

3 years ago