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katrin [286]
4 years ago
5

Can TDS heavy metals be removed from wastewater without the addition of chemicals Ph 2.3. Want to reuse water

Chemistry
1 answer:
Arte-miy333 [17]4 years ago
7 0
<span>Yes, TDS heavy metals can be removed from water through electrocoagulation treatment. During electrocoagulation treatment, an electrical charge is applied to the polluted water which causes the dissolved substances such as heavy metals to coagulate into an agglomeration that can be removed without the use of filters and chemicals.</span>
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Which of these phrases would go in the overlap? Select two options.
SVETLANKA909090 [29]
I think it’s found in the nucleus and has a mass of one amu
5 0
2 years ago
Read 2 more answers
How can you calculate the energy of an electron who moved from E1 to E5?
puteri [66]

Answer:

See explanation

Explanation:

If the energy of the ground state E1 is known, then we need to measure the difference in energy between the energy levels E5 .and E1. We can obtain this by measuring the frequency or wavelength of a photon that is emitted when an electron moves from energy level E5 to E1.

From Bohr's model;

ΔE = E5 - E1

Hence;

E5 = ΔE + E1

7 0
3 years ago
A piston contains 0.39L of air at 1.0 atm. If the pressure on the piston is increased to 5.6 atm, what is the new volume?
bazaltina [42]

The new volume : 0.07 L

<h3>Further explanation</h3>

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

P₁=1 atm

V₁=0.39 L

P₂=5.6 atm

\tt V_2=\dfrac{P_1.V_1}{P_2}\\\\V_2=\dfrac{1\times 0.39}{5.6}\\\\v_2=\boxed{\bold{0.07~L}}

3 0
4 years ago
Substance A has the following properties.
ella [17]

It will take 1.11 min to heat the sample to its melting point.

Melting point = - 20°C

Boiling point = 85°C

∆H of fusion = 180 J/g

∆H of vap = 500 J/g

C(solid) = 1.0 J/g °C

C(liquid) = 2.5 J/g °C

C(gas) = 0.5 J/g °C

Mass of sample = 25 g

Initial temperature = - 40°C

Final temperature = 100°C

Rate of heating = 450 J/min

Specific heat capacity formula:- q = m ×C×∆T

Here, q = heat energy

        m = mass

        C = specific heat

      ∆T = temperature change

Melting point = - 20°C

C(solid) = 1.0 J/g °C

∆T = final temperature - initial temperature = -20 - (-40) = 20

Put these value in  Specific heat capacity formula

q = m ×C×∆T

q = 25×1.0×20

   =500J

The Rate of heating = 450 J/min

i.e. 450J = 1min

so, 500J = 1.11min

1.11 minutes does it take to heat the sample to its melting point.

The specific heat capacity is defined as the amount of heat absorbed in line with unit mass of the material whilst its temperature increases 1 °C.

Learn more about specific heat capacity here:- brainly.com/question/26866234

#SPJ4

3 0
2 years ago
What does not add co2 to the atmosphere
marissa [1.9K]

Answer:

Abiotic objects

Ex. bed, table, lamp, chair, blanket, etc.

Abiotic means Non-living.

7 0
2 years ago
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