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2 years ago

This is for girls only!!!!!! if you are a boy go away

Chemistry

2 answers:

Julli [10]2 years ago

6 0

There’s not much I can do with a body as I can with money

$$$$$$$$$$$$$

Sladkaya [172]2 years ago

4 0

Money so i can get a nice body with the money hahah

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PLEASE HELP!!!!!! WILL AWARD BRAINLIEST!!!!!!

asambeis [7]

Answer:

A. Sedimentry rock

b. high pressure

Explanation:

6 0

3 years ago

Given the equation I = Q/t, solve for t.

larisa86 [58]

Answer: $t=\frac{Q}{I}$

Explanation:

$I=\frac{Q}{t}$

Multiply by t on both sides.

$t*I=\frac{Q}{t}*t$

$tI=Q$

Now divide by I to isolate t.

$\frac{tI}{I}=\frac{Q}{I}$

$t=\frac{Q}{I}$

5 0

3 years ago

A 50-mL beaker only has a scale that measures 10, 20, 30, and 40 mL. What is the uncertainty associated with the 50 mL beaker.

Juliette [100K]

If the uncertainty of a certain measurement instrument is not given, then it is assumed to be equal to half of the least count of that instrument. In this case, the least count is 10 ml, so half of this is 5 ml. Therefore, the graduated cylinder has an uncertainty of +/- 5 ml

8 0

3 years ago

Which models of the atom include a structure that is mostly made of empty space?RutherfordThomsonBohrQuantum mechanical

Luba_88 [7]

<h2>Answer:</h2>

Rutherford's models

<h2>Explanations:</h2><h2>What is the electron cloud model?</h2>

There are known as the region where electrons are found especially in the nucleus.

According to the five basic atomic models which have contributed to the structure of the atom itself, the Rutherford's models of the atom include a structure that is mostly made of empty space compared to thomson that proposed the plum pudding model of the atom

4 0

1 year ago

Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

3 years ago