Answer:
15 minutes
Step-by-step explanation:
Their rate together is 1/6 floor per minute.
Her rate alone is 1/10 floor per minute.
His rate is the difference of these:
1/6 - 1/10 = 5/30 -3/30 = 2/30 = 1/15 . . . . floor per minute
It would take Jacob 15 minutes to do it alone.
Answer:
The ladder has to be 65 feet long to the nearest foot.
Step-by-step explanation:
The height of the chimney from the ground is the sum of the height of the wall and the height of the chimney.
Therefore, the height of the chimney from the ground = (30 + 33) = 63 feet.
Now, the ladder makes a right triangle with the ground and the chimney and the ladder makes an angle of 75.5° with the ground.
Therefore, using trigonometry we can write,

⇒ The length of the ladder = 65 feet.
Hence, the ladder has to be 65 feet long to the nearest foot. (Answer)
If you divide 35 (amount of detergent in the container )into 1.25 (the 1 1/4 cups) your answer would be that you can do 28 loads , and if you had 3 boxes you would be able to do 84 loads because you just need to multiply the previous answer by 3
Answer:
Volume = 
Step-by-step explanation:
Given - Consider the solid S described below. The base of S is the triangular region with vertices (0, 0), (4, 0), and (0, 4). Cross-sections perpendicular to the x-axis are squares.
To find - Find the volume V of this solid.
Solution -
Given that,
The equation of the line with both x-intercept and y-intercept as 4 is -

⇒x + y = 4
⇒y = 4 - x
Now,
Volume = 
where
A(x) is the area of general cross-section.
It is given that,
Cross-sections perpendicular to the x-axis are squares.
So,
A(x) = (4 - x)²
As solid lies between x = 0 and x = 4
So,
The Volume becomes
Volume = 
= ![\int\limits^4_0 {[(4)^{2} + (x)^{2} - 8x] } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_0%20%7B%5B%284%29%5E%7B2%7D%20%20%2B%20%28x%29%5E%7B2%7D%20-%208x%5D%20%7D%20%5C%2C%20dx)
= ![\int\limits^4_0 {[16 + x^{2} - 8x] } \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E4_0%20%7B%5B16%20%20%2B%20x%5E%7B2%7D%20-%208x%5D%20%7D%20%5C%2C%20dx)
= ![{[16 x + \frac{x^{3}}{3} - \frac{8x^{2} }{2} ] } ^4_0](https://tex.z-dn.net/?f=%7B%5B16%20x%20%20%2B%20%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D%20%20-%20%5Cfrac%7B8x%5E%7B2%7D%20%7D%7B2%7D%20%5D%20%7D%20%5E4_0)
= ![{[16(4 - 0) + \frac{4^{3}}{3} - \frac{0^{3}}{3} - 4 [4^{2} - 0^{2}] ] }](https://tex.z-dn.net/?f=%7B%5B16%284%20-%200%29%20%20%2B%20%5Cfrac%7B4%5E%7B3%7D%7D%7B3%7D%20-%20%5Cfrac%7B0%5E%7B3%7D%7D%7B3%7D%20%20-%204%20%5B4%5E%7B2%7D%20-%200%5E%7B2%7D%5D%20%20%20%5D%20%7D)
= ![{[16(4) + \frac{64}{3} - 0 - 4 [16 - 0] ] }](https://tex.z-dn.net/?f=%7B%5B16%284%29%20%20%2B%20%5Cfrac%7B64%7D%7B3%7D%20-%200%20%20-%204%20%5B16%20-%200%5D%20%20%20%5D%20%7D)
= ![{[64 + \frac{64}{3} - 64 ] }](https://tex.z-dn.net/?f=%7B%5B64%20%20%2B%20%5Cfrac%7B64%7D%7B3%7D%20%20-%2064%20%20%5D%20%7D)
= 
⇒Volume = 