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3 years ago

The area of a rectangle is 40 cm2. If its length is 10 cm, what is its width?

Mathematics

1 answer:

astra-53 [7]3 years ago

3 0

Answer:

Width = 4 cm

Step-by-step explanation:

The formula for area of a rectangle is length x width. You have the length (10), leaving you with this equation.

10 x ? = 40

Solve for x, or in other words, divide 40 by 10. This gives you 4. This means that 10 x 4 equals 40 cm^2

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In circle R with m angle QRS= 90 and QR= 3 units find the length of arc QS round to the nearest hundredth

Advocard [28]

Answer:

4.71 units

Step-by-step explanation:

The formula for arc length =

2πr × θ/360

From the above question,

r = QR = 3 units

θ = angle QRS= 90 = 90°

The length of the arc is calculated as:

2 × π × 3 × 90/360

= 4.7123889804 units

Approximately to the nearest hundredth = 4.71 units

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3 years ago

Each side of the regular hexagon below measures 8 cm. What is the area of the hexagon?

sineoko [7]

A regular hexagon can be split into 6 congruent equilateral triangles.
the area of an equilateral triangle is √3*s²/4, where s is the side length
Area of the hexagon
= 6*√3*8²/4
= 96√3 square centimeters

6 0

3 years ago

Read 2 more answers

5. Find the volume, of a cone with a radius of 3 yards and a height of 11 yards.

Zigmanuir [339]

ANSWER: Solve for volume

V≈79.26m³

4 0

2 years ago

Which of the following is the solution to the differential equation dP/dt+P=10 with the initial condition P(0)=4

Ber [7]

Answer:

Option C. $P=10-6e^{-t}$

Explanation:

1. Separate variables:

$\dfrac{dP}{dt}+P=10\\ \\ \\ \\\dfrac{dP}{dt}=-P+10\\ \\ \\ \dfrac{dP}{-P+10}=dt$

2. Find the indefinite integrals

$-\ln{(10-P)}=t+C$

3. Solve for P

$10-P=e^{-t+C}\\ \\ 10-P=Ke^{-t}\\ \\ P=10-Ke^{-t}$

4. Use the initial condition, P(0) = 4, to find K:

4 = 10 - K(e⁰)

4 = 10 - K

K = 10 - 4

K = 6

5. Substitute K = 6 into the integrated equation:

$P=10-6e^{-t}$

That is the option C.

4 0

3 years ago

A GROUP OF STATISTICS STUDENTS DECIDED TO CONDUCT A SURVEY AT THEIR UNIVERSITY TO FIND THE AVERAGE (MEAN) AMOUNT OF TIME STUDENT

Kay [80]

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

n = 240

mean = 22.3 hours

standard deviation = 6 hours

At 99% level of confidence, z = 2.58

So, interval would be

$\bar{x}\pm z\dfrac{\sigma}{\sqrt{n}}\\\\=22.3\pm 2.58\times \dfrac{6}{\sqrt{240}}\\\\=22.3\pm 0.99\\\\=(22.3-0.99,22.3+0.99)\\\\=(21.31,23.29)$

Hence, Option 'c' is correct.

3 0

3 years ago