Answer:
x = 15
Step-by-step explanation:
Answer:
To find critical points, take the first derivative and set it equal to zero:
f(x) = -2x^2 + 4x + 5
f'(x) = -4x + 4
-4x+4 = 0
-4x = -4
x = 1
Critical point at x = 1
Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.
Answer:
Either y =
or, y =
Step-by-step explanation:
We have to solve the following quadratic equation
45y² + 15y - 10 =0
Now, dividing both sides with 5 we get, 9y² + 3y -2 =0
Hence, to solve the above equation we have to factorize the left-hand part of the equation.
So, 9y² + 3y - 2 =0
⇒ 9y² +6y -3y -2 =0
⇒ (3y +2) (3y -1 ) =0
⇒ Either (3y +2) =0 or (3y -1) =0
⇒ Either y =
or, y =
(Answer)
Answer:
A, y = 3x/2 - 12
Step-by-step explanation:
Use the equation y = mx + b.
m = 3/2
b = -12
y = 3x/2 - 12
Answer: Idek if that's a question
Step-by-step explanation: