Answer:
69420
Step-by-step explanation:
Your biological birth Mother
Pretty sure the mean is 8
Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that
74% of student are taking an English class
This means that
70% of students are taking both
This means that
Find the probability that a randomly selected student is taking a math class or an English class.
This is , which is given by:
So
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Answer: y=x+1
Step-by-step explanation:
y+1=1(x+2)
y+1=x+2
y=x+1
Hope this helps:)
Answer:
Step-by-step explanation:
(1450-50) ÷ 8= x. Is x greater than 200? If not, then subtract x from 200. That's your answer