The equation will be of the form:

where A is the amount after t hours, and r is the decay constant.
To find the value of r, we plug the given values into the equation, giving:

Rearranging and taking natural logs of both sides, we get:


The required model is:
Answer:
-120
Step-by-step explanation:
subtract 45 to both sides
m/8 = -15
multiply by 8 on both sides.
with the fraction just multiply by the bottom number to make m by itself.
m = -15*8
m= -120