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Mekhanik [1.2K]
3 years ago
13

I’d really appreciate help with these...

Mathematics
2 answers:
Irina-Kira [14]3 years ago
7 0

Answer:

+- 5 and +- 3

Step-by-step explanation:

qn 2:

4r² = 91 + 9

4r² = 100

r² = 25

r = +- 5

qn 3:

4r² = 29 + 7

4r² = 36

r² = 9

r = +- 3

vovikov84 [41]3 years ago
4 0

Answer:

<h2>Q2. (±5)</h2><h2>Q3. (±3)</h2>

Step-by-step explanation:

\bold{Q2.}\\\\4r^2-9=91\qquad\text{add 9 to both sides}\\\\4r^2-9+9=91+9\\\\4r^2=100\qquad\text{divide both sides by 4}\\\\\dfrac{4r^2}{4}=\dfrac{100}{4}\\\\r^2=25\to r=\pm\sqrt{25}\\\\\boxed{r=\pm5}

\bold{Q3.}\\\\4r^2-7=29\qquad\text{add 7 to both sides}\\\\4r^2-7+7=29+7\\\\4r^2=36\qquad\text{divide both sides by 4}\\\\\dfrac{4r^2}{4}=\dfrac{36}{4}\\\\r^2=9\to r=\pm\sqrt9\\\\\boxed{r=\pm3}

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Reduce 25\ 1000 to its lowest terms​
denis-greek [22]

Answer:

The answer would be 1/40 I believe. Hope this helps :)

Step-by-step explanation:

7 0
3 years ago
I have 8 pennies and some quarters, nickels, and dimes. The number of pennies plus nickels equals the number of dimes. I have 3
Darina [25.2K]

There are five nickels.

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Then, we have three equations with four unknowns:

(1) <em>w</em> + <em>x = y </em>

(2) 3<em>w</em> = 2<em>z</em>

(3) 2<em>y</em> = 3<em>z</em>

However, there is a fourth <em>unstated </em>condition: <em>w</em>, <em>x</em>, y, and <em>z</em> must all be integers.

Assume that z = 6 (to avoid fractions).

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<em>Check</em>: 4 pennies + 5 nickels = 9 dimes

6 quarters + 4 pennies = 3 quarters for every 2 pennies

9 dimes + 6 quarters = 3 dimes for every 2 quarters

5 0
3 years ago
Read 2 more answers
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Veseljchak [2.6K]
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3 years ago
Read 2 more answers
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Burka [1]

Answer:

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+ x° + x°

______________

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-90° - 90°

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6 0
3 years ago
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ANSWER:

EXPLANATION:

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