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Mekhanik [1.2K]
3 years ago
13

I’d really appreciate help with these...

Mathematics
2 answers:
Irina-Kira [14]3 years ago
7 0

Answer:

+- 5 and +- 3

Step-by-step explanation:

qn 2:

4r² = 91 + 9

4r² = 100

r² = 25

r = +- 5

qn 3:

4r² = 29 + 7

4r² = 36

r² = 9

r = +- 3

vovikov84 [41]3 years ago
4 0

Answer:

<h2>Q2. (±5)</h2><h2>Q3. (±3)</h2>

Step-by-step explanation:

\bold{Q2.}\\\\4r^2-9=91\qquad\text{add 9 to both sides}\\\\4r^2-9+9=91+9\\\\4r^2=100\qquad\text{divide both sides by 4}\\\\\dfrac{4r^2}{4}=\dfrac{100}{4}\\\\r^2=25\to r=\pm\sqrt{25}\\\\\boxed{r=\pm5}

\bold{Q3.}\\\\4r^2-7=29\qquad\text{add 7 to both sides}\\\\4r^2-7+7=29+7\\\\4r^2=36\qquad\text{divide both sides by 4}\\\\\dfrac{4r^2}{4}=\dfrac{36}{4}\\\\r^2=9\to r=\pm\sqrt9\\\\\boxed{r=\pm3}

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The height, h, in feet of a rock above the ground is given by the equation h = -16t^2 + 24t + 16, where t is the time in seconds
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Explanation:

Given that the height, h, in feet of a rock above the ground is given by the equation h=-16t^2+24t+16, where t is the time in seconds after the rock is thrown.

We need to determine the time at which the rock will hit the ground.

To determine the time, let us equate the height h = 0 in the equation h=-16t^2+24t+16, we get,

0=-16t^2+24t+16

Switch sides, we have,

-16 t^{2}+24 t+16=0

Let us solve the equation using the quadratic formula.

Thus, we have,

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t=\frac{-24 \pm \sqrt{576+1024}}{-32}

t=\frac{-24 \pm \sqrt{1600}}{-32}

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Dividing, we get,

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Since, t cannot negative values, we have,

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