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3 years ago

Create an equation that you can use in everyday life. Then solve it.

Mathematics

1 answer:

galina1969 [7]3 years ago

5 0

If you were to plan a party, you could use a linear equation. for example, the room you are renting is $500. The price for food per person is $10

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Stanley can purchas a 15.4-ounce bottle of

sp2606 [1]

Answer: They are the same deal

Step-by-step explanation:

15.4/5.39=3.33333...

23.6/7.08=3.333333...

5 0

2 years ago

I need help please.

Zarrin [17]

Answer:

i think this is it

Step-by-step explanation:

the answer i got is just 55

3 0

4 years ago

Evaluate the integral using the indicated trigonometric substitution. (use c for the constant of integration.) x^3 / sqrt x^2 +

slava [35]

$\displaystyle\int\frac{x^3}{\sqrt{x^2+49}}\,\mathrm dx$

Taking $x=7\tan\theta$ gives $\mathrm dx=7\sec^2\theta\,\mathrm d\theta$ , so that the integral becomes

$\displaystyle\int\frac{(7\tan\theta)^3}{\sqrt{(7\tan\theta)^2+49}}(7\sec^2\theta)\,\mathrm d\theta$
$=\displaystyle7^4\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{49\tan^2\theta+49}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\tan^2\theta+1}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sqrt{\sec^2\theta}}\,\mathrm d\theta$
$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{|\sec\theta|}\,\mathrm d\theta$

When $\sec\theta>0$ , we have

$=\displaystyle7^3\int\frac{\tan^3\theta\sec^3\theta}{\sec\theta}\,\mathrm d\theta$
$=\displaystyle7^3\int\tan^3\theta\sec^2\theta\,\mathrm d\theta$

and from here we can substitute $u=\tan\theta$ to proceed from here.

Quick note: When we set $x=7\tan\theta$ , we are implicitly enforcing $-\dfrac\pi2$ just so that the substitution can be undone later via $\theta=\tan^{-1}\dfrac x7$ . But note that over this domain, we automatically guarantee that $\sec\theta>0$ , so the absolute value bars can be dropped immediately.

6 0

3 years ago

Three and two sevenths plus eight and one third

quester [9]

Eleven and thirteen over 21

5 0

3 years ago

Read 2 more answers

a ABC company stock dropped from 25 3/8 to 22 1/4 during a one month period of time so how much stock fall during this period of

OLEGan [10]

First, let's convert the mixed fraction into an improper fraction (trust me, mixed fraction are pretty much the worst things to deal with, especially with higher level math):
$25 \frac{3}{8} = \frac{203}{8}$
$22 \frac{1}{4} = \frac{89}{4}$

Then, to subtract, since you need a common denominator, I would multiply the second fraction by 2 to get:
$2 (\frac{89}{4} ) = \frac{178}{8}$

Now that we have a common denominator, we are ready to subtract:
$\frac{203}{8} - \frac{178}{8} = \frac{25}{8}$

Since that's the most simplified form, and you have been asked the question in a mixed fraction form, let's convert that to a mixed fraction. The remainder of the numerator divided by the denominator is 1, and the quotient is 3. The denominator stays the same. So, this is what results:
$3 \frac{1}{8}$

And that's your answer: $3 \frac{1}{8}$

Hope this all makes sense. If anything doesn't, feel free to tell me!

7 0

3 years ago