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4 years ago

Yooooo im soo bored someone talk to me plz

Mathematics

2 answers:

Ne4ueva [31]4 years ago

7 0

Answer:

sure!

Step-by-step explanation:

xenn [34]4 years ago

7 0

Answer:

i am bored as well

Step-by-step explanation:

i am bored and i am doing nothing how about you

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Tanya paid $75 to join a summer gold program. The course where she plays charges $30 per round. Since she is a student, she rece

Crazy boy [7]

Tanya played 15 rounds.
375-75=300
30-10=20
300÷20=15

8 0

4 years ago

Mrs. Toomer brought 40 cookies to school. Mrs. Toomer's class ate 1/2 the cookies. Mrs. Wilson's class ate 1/4 of the remaining

Arte-miy333 [17]

1/2 of 40 is 20, and the question says 1/4 of the REMAINING cookies, and 1/4 of 20 is 5. There are 3/4 left, or 15 cookies. I hope this helps!

3 0

3 years ago

Read 2 more answers

What’s the fifth term of a sequence whose first term is 5 and whose common ratio is 3?

SSSSS [86.1K]

Answer:

405.

Step-by-step explanation:

This is a geometric sequence where the nth term = a1 r^(n -1).

Here a1 = 5 and r = 3 so

the fifth term a5 = 5(3)^(5-1)

= 5 * 81

= 405.

4 0

3 years ago

Is the given function phi(x) = x^2 - x^-1 an explicit solution to the linear equation d^2y/dx^2 - 2/x^2 y = 0? Circle your answe

mart [117]

Answer:

Yes

Step-by-step explanation:

We are given that a function $\phi(x)=x^2-x^{-1}$

We have to find that given function is an explicit solution to the linear equation

$\frac{d^2y}{dx^2}-\frac{2}{x^2}y=0$

If given function is an explicit solution of given linear equation then it satisfied the given differential equation

Differentiate w.r.t x

Then we get $\phi'(x)=2x+x^{-2}$

Again differentiate w.r.t x

Then we get

$\phi''(x)=2-\frac{2}{x^3}$

Substitute all values in the given differential equation

$2-\frac{2}{x^3}-\frac{2}{x^2}(x^2-x^{-1})$

= $2-\frac{2}{x^3}-2+\frac{2}{x^3}=0$

Hence, given function is an explicit solution of given differential equation.

Therefore, answer is yes.

3 0

3 years ago

What is the difference?

ANTONII [103]

$- \frac{1}{10} - (- \frac{2}{10} ) = \frac{1}{10} + (-\frac{2}{10}) = - \frac{1}{10}$

3 0

3 years ago