The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Answer:

Step-by-step explanation:
It's an arithmetic sequence.

The difference is constant.
The explicit formula of an arithmetic sequence:

Substitute:

<em>use distributive property</em>

Answer:
sdddddddddddddddddddddddddssa
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
1. go to desmos Graphing calculator and select graphing calculator
2. Next type in the word length then it should look like this Length
3. Don't space just put this ( and type in the point it should look like this Length(-2,-3),(4,4)
4. Be sure to do double () it should look like this Length((-2,-3),(4,4))
5. It should give you your answer