This represents a function with a slope of 2 and y-intercept of 1
Surface area of cylinder is given by area of circle + area of the rectangle that curved around the cylinder
Area of the base of the cylinder =

Area of the cylinder 'wall' = width × length =

×

=

×

=

Note that the wall of the cylinder is in the shape of a rectangle. The width of the rectangle is the height of the cylinder. The length of the rectangle is the circumference of the circle base.
Surface area of cone is given by

where

is the slanted height of the cone
SA of cone =

Hence total painted surface area is
Answer:
k = 12
Step-by-step explanation:
Given:
The equation 
To find:
Value of
for which the given equation has one distinct real solution.
Solution:
The given equation is a quadratic equation.
There are always two solutions of a quadratic equation.
For the equation:
to have one distinct solution:

Here,
a = 2,
b = -k and
c = 18
Putting the values, we get:

The equation becomes:

And the one root is:

Answer:
The answer to your question is the letter E. 50
Step-by-step explanation:
Data
height = ?
Width = 80 cm
Length = 40 cm
Volume = 160000 cm³
Formula
Volume of a rectangular prism = Width x length x height
Substitution
160000 = 80 x 40 x height
Solve for height
height = 160000 / 80 x 40
Simplification
height = 160000/ 3200
Result
height = 50 cm
The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________