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Pani-rosa [81]
3 years ago
6

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to kno

w which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it's $245. How many fries (x) and shakes (y) did they sell?
Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

The number of fries and shakes sold are 70 and 35 respectively.

Step-by-step explanation:

The number of fries sold can be denoted by <em>x</em>.

The number of shakes sold can be denoted by <em>y</em>.

The equation representing the total number of items sold is:

<em>x</em> + <em>y</em> = 105...(i)

The cost fries is, $2.

The cost of shakes is, $3.

The equation representing the total money earned is:

2<em>x</em> + 3<em>y</em> = 245...(ii)

Solve equations (i) and (ii) simultaneously as follows:

Multiply equation (i) by 3 and subtract:

3x + 3y = 315

2x + 3y = 245

(-)     (-)      (-)

___________

x = 70

Compute the value of <em>y</em> as follows:

x + y = 105

70 + y = 105

y = 105 - 70

y = 35

Thus, the number of fries and shakes sold are 70 and 35 respectively.

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Answer:

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Step-by-step explanation:

Just add 8 to 28 = 36

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hope this helps

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enot [183]

Answer:

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Step-by-step explanation:

Tbh I don't know the answer I just hope this helps

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