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Pani-rosa [81]
3 years ago
6

ASB is selling In-N-Out as a fundraiser. Fries cost $2 and shakes cost $3. Students can only buy one item each. ASB wants to kno

w which sells better but they lose track of what they sold. They know 105 students bought either fries or a shake. They count their money and it's $245. How many fries (x) and shakes (y) did they sell?
Mathematics
1 answer:
AURORKA [14]3 years ago
5 0

Answer:

The number of fries and shakes sold are 70 and 35 respectively.

Step-by-step explanation:

The number of fries sold can be denoted by <em>x</em>.

The number of shakes sold can be denoted by <em>y</em>.

The equation representing the total number of items sold is:

<em>x</em> + <em>y</em> = 105...(i)

The cost fries is, $2.

The cost of shakes is, $3.

The equation representing the total money earned is:

2<em>x</em> + 3<em>y</em> = 245...(ii)

Solve equations (i) and (ii) simultaneously as follows:

Multiply equation (i) by 3 and subtract:

3x + 3y = 315

2x + 3y = 245

(-)     (-)      (-)

___________

x = 70

Compute the value of <em>y</em> as follows:

x + y = 105

70 + y = 105

y = 105 - 70

y = 35

Thus, the number of fries and shakes sold are 70 and 35 respectively.

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3 years ago
Geraldo recently saw a newspaper ad for a new version of his laptop. the projected price is $400.00, and the laptop will be out
Tanya [424]

The amount he had to pay if he have to purchase a laptop today that is the same value as the one he saw in the ad is $ 390.24.

Given that:-

Price of the laptop after 1 year = $ 400.

Inflation rate = 2.5 %

We have to find the amount he had to pay if he have to purchase a laptop today that is the same value as the one he saw in the ad.

Let the price he had to pay be x.

Hence, we can write,

x + (x*(2.5)*1)/100 = 400

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1 year ago
Find the value of the missing side-Use SOH CAH TOA
Vanyuwa [196]

Answer:

4.04 (idk how you want it rounded)

Step-by-step explanation:

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the equation should look like: Tan30= x/7

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5 0
3 years ago
Read 2 more answers
Simplify.<br> Rewrite the expression in the form b^n<br><br> (b^3)^2
Alexxandr [17]

Step-by-step explanation:

a^n={\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}

<h2>METHOD 1.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=\underbrace{b\cdot b\cdot b}_{3}\cdot\underbrace{b\cdot b\cdot b}_{3}=\underbrace{b\cdot b\cdot b\cdot b\cdot b\cdot b}_{6}=b^6

<h2>METHOD 2.</h2>

\left(b^3\right)^2=\underbrace{b^3\cdot b^3}_{2}=b^{3+3}=b^6\qquad\text{used}\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 3.</h2>

\left(b^3\right)^2=\left(\underbrace{b\cdot b\cdot b}_{3}\right)^2=b^2\cdot b^2\cdot b^2=b^{2+2+2}=b^6\\\text{used}\ (ab)^n=a^nb^n,\ a^n\cdot a^m=a^{n+m}

<h2>METHOD 4.</h2>

\left(b^3\right)^2=b^{3\cdot2}=b^6\qquad\text{used}\ \left(a^n\right)^m=a^{nm}

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3 years ago
Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
lutik1710 [3]
<h3>Answer: Choice C</h3>

cos(a - b) = cos(a)cos(b) + sin(a)sin(b)

In this case, we'd have a = 180 and b = q, so,

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

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cos(180 - q) = -1*cos(q) + 0*sin(q)

cos(180 - q) = -cos(q) + 0

cos(180 - q) = -cos(q)

8 0
3 years ago
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