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andrey2020 [161]
3 years ago
11

Find the value of the missing side-Use SOH CAH TOA

Mathematics
2 answers:
Vanyuwa [196]3 years ago
5 0

Answer:

4.04 (idk how you want it rounded)

Step-by-step explanation:

1) Use TOA

the equation should look like: Tan30= x/7

2) multiply each side by 7 and you’re left with 7Tan30= x

3) in your calculator do 7x30Tan equals and you get your answer

Sladkaya [172]3 years ago
5 0
Oh can’t really read it
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500/25=100/y<br> help me in this :(
kupik [55]

Answer:

\boxed{\boxed{\sf  1  \ by \ 2  }}

500/25 = 100/y

100/5 = 100/y

20 = 100/Y

200/1 = 100/Y

By cross multiplication

200 × Y = 100 × 1

Y = 100 /200

Y = 1/2

6 0
3 years ago
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Maybe try using Photomath it works for me. Good luck
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Answer:

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Step-by-step explanation:

8 0
3 years ago
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What number multiplied by itself 3 times equals-343
professor190 [17]
343*3=1029 this is the answer 
7 0
3 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
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