Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
The answer to the math problem is 10.35
Answer:
32 divided by 4 = 8,
8^2 + 8^2 = 128
128: 11^2 = 121 close enough, 11 is your answer
We are finding hypotenuse but first we find the length of all sides of the two squares to find the two sides of the triangle then we find hypotenuse.
If your question is 25 dollars for the shirt then the ansewer is $26.5 hope this helps.