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Varvara68 [4.7K]
3 years ago
10

PLEASEEEE HURRYYYY!!!!find the slope, y and x-intercept off(x)=4 ​

Mathematics
1 answer:
Tju [1.3M]3 years ago
7 0

i'd say it would be 4 over 1         4/1    so you go up 4 and to the right 1 if they were negative then it would be the oposite way around.

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Find the area of the shape shown below.
Shtirlitz [24]

Answer:

6 + 2 = 8 x 2 = 16 divided by 2 = 8

Step-by-step explanation:

Formula of a trapezoid:

B1(base 1) + B2(base 2) x H (Height) x 1/2 (basically dividing by 2)

5 0
3 years ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
3 years ago
Y &gt; -x + 2<br>y &lt; 3x - 2<br>Which graph represents the system of inequalities?<br>​
SashulF [63]

Answer:

C

Step-by-step explanation:

When an equality has a ≤, or ≥ sign (greater than/less than or equal to), the line will be solid. When an equality has a <, or > sign(greater than/less than), the lines will be dotted. As we can see, both of the inequalities given have <, or >, meaning they must both have dotted lines. Since one of the lines in D is solid, the correct answer is C.

3 0
3 years ago
Read 2 more answers
Given a long algebraic equation, what are some strategies that you can use to make simplifying and evaluating the equation more
Alexandra [31]
1. use PEMDAS to do the problem in the correct order, put like terms together
2. Inverse operations help by plugging the value back into the equation and ensuring you have the right answer.
3. Construction workers may do the inverse to make sure they have the correct measurements for walls or something.
6 0
4 years ago
Read 2 more answers
2 cans of paint hold 64 and 125 oz. if the cans are similar cylinders and the smaller lid has an area of 18 find the area of the
kramer

Answer:

The area of the bigger lid is approximately 29.2 square inches

Step-by-step explanation:

The given data are;

The volume held by one of the cans of paint, V₁ = 64 oz

The volume held by the other cans of paint, V₂ = 125 oz

The area of the smaller lid = 18 in²

Therefore,

The 64 Oz = The smaller can of paint

The 125 oz = The larger can of paint

The diameter of the smaller lid, d₁ = √(18 × 4/π) ≈ 4.787

The ratio of can volumes = (The ratio of can diameters)³

V₁/V₂ = (d₁/d₂)³

V₁/V₂ = 64/125

d₁/d₂ ≈ 4.787/d₂

64/125 = (4.787/d₂)³

4.787/d₂ = ∛(64/125) = 4/5

d₂ ≈ 4.878×5/4 = 6.0975

The area of the bigger lid, A₂ = π·d₂²/4

∴ A₂ = π × 6.0975²/4 ≈ 29.2

The area of the bigger lid, A₂ ≈ 29.2 in.²

6 0
3 years ago
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