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Artyom0805 [142]
3 years ago
13

Let be the func

tion defined by f(x)=\sqrt{x}. What is the approximation for the value of \sqrt{3} obtained by using the second-degree Taylor polynomial for f about x=4?
Mathematics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

Step-by-step explanation:

The Taylor series at x=4 is

\sqrt{x} = 2 + \frac{x-4}{4}  - \frac{(x-4)^2}{64}  + ...

So,

\sqrt{3} = 2 - \frac{1}{4} - \frac{1}{64} = 1.73

Not too bad, eh?

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