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kipiarov [429]
3 years ago
6

Find a counterexample to show that the following statement is false. The sum of two five-digit numbers is a six-digit number + i

s a five-digit number ents cess Library ccess tesources ptions
Mathematics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

It not necessary that every time the sum of two five digit number is a six digit number.

Step-by-step explanation:

We are given the statement that sum of two five digit numbers is always a six digit number.

We have to give a counter example to show that the given statement is false.

It not necessary that every time the sum of two five digit number is a six digit number.

Example:

10,000 + 30,000 = 40,000

13,245 + 74,632 = 87,877

56463 + 26230 = 82693

50,000 + 50,000 = 1,00,000

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from a group of 25 men,12 were to be given gifts.What is the probability of choosing a man who did not a gift​
nikklg [1K]
Answer: 13/25

Explanation:

There are 25 men in total
12 were to be given gifts

Find the probability of choosing a man who did not receive a gift:

P = 25/25 - 12/25 = 13/25
6 0
3 years ago
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PLEASE HELP!!! very confused
Leni [432]

Answer:

Step-by-step explanation:

The vertices lie on the x-axis, as is determined by their coordinates. This makes the center of this hyperbola (0, 0) because the center is directly between the vertices. The fact that the foci also lie on the x-axis tells us that this is the main axis. What this also tells us is which way the hyperbola "opens". This one opens to the left and the right as opposed to up and down. The standard form for this hyperbola is:

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1 and so far we have that h = 0 and k = 0.

By definition, a is the distance between the center and the vertices. So a = 5, and a-squared is 25. So we're getting there. Now here's the tricky part.

The expressions for the foci are (h-c, k) and (h+c, k). Since we know the foci lie at +/-13, we can use that to solve for c:

If h+c = 13 and h = 0, then

0 + c = 13 and c = 13.

We need that c value to help us find b:

c^2=a^2+b^2 and

13^2=5^2+b^2 and

169=25+b^2 and

144=b^2 so

b = 12. Now we're ready to fill in the equation:

\frac{x^2}{25}-\frac{y^2}{144}=1 and there you go!

3 0
2 years ago
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prohojiy [21]

Answer:

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Step-by-step explanation:

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3 years ago
The cost of a toy is $20 less than 2 times the cost of a toy train. If the cost of the toy car is $100, what is the cost of the
kiruha [24]
The toy is 2(x)-20, x is 100, being the toy car. So 2(100)= 200 -20 =180. The cost of the toy is $180
5 0
3 years ago
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Please help me complete this !! 12points
Svet_ta [14]

Answer:

1.

x1=1

x2=3

y1=5

y2=1

midpoint= (x1+x2/2, y1+y2/2)=(1+3/2,5+1/2)=(2,3)

2.

x1=2

x2=4

y1=4

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(2+4/2,4+6/2)=(3,5)

3.

x1= -2

x2=4

y1=4

y2= -6

midpoint= (x1+x2/2, y1+y2/2)=(-2+4/2,4-6/2)=(1,-1)

4.

x1=0

x2=0

y1=3

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(0/2,3+5/2)=(0,4)

5.

x1= -2

x2=2

y1= -6

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(-2+2/2,-6+6/2)=(0,0)

6.

x1=1

x2=4

y1=4

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(1+4/2,4+5/2)=(5/2,9/2)

7.

x1=-3

x2=-4

y1=5

y2=5

midpoint= (x1+x2/2, y1+y2/2)=(-3-4/2,5+5/2)=(-7/2,5)

8.

x1=5

x2= -4

y1=2

y2=6

midpoint= (x1+x2/2, y1+y2/2)=(5-4/2,2+6/2)=(1/2,4)

3 0
2 years ago
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