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3 years ago

Help me plis un algebra

Mathematics

1 answer:

stellarik [79]3 years ago

3 0

Answer:

Step-by-step explanation:

Add the given numbers to the last recorded temp and see what is closest to 100 degrees.

95.5 + 6.5 = 101.5

95.5 + 6.6 = 102.1

95.5 + 5.5 = 101

95.5 + 5 = 100.5

So the closest to 100 degrees would be 5.

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What is the image of N for a 300° counterclockwise rotation about the center of the regular hexagon? Will give brainiest only if

OLEGan [10]

Answer:

Step-by-step explanation:

here, the question says that the given regular hexagon needs to be rotated counter clockwise 300°, considering the edges labels, each movement from one edge to other is 60° as 360/6 =60.

focus on N and move on anti clockwise.

When N rotates anti clockwise about center from original to position G, is 60°,

when N moves on anti clockwise about center from original to position A is 120°.

similarly, to X is 180°, to E is 240° and to H is 300°.

so, the new position of N when rotated anti clockwise about origin of the hexagon will be at H.

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4 years ago

Jocelyn calculates that see will take 105 minutes to run 7 miles. She runs the distance in 84 minutes. What is Jillian’s percent

VladimirAG [237]

Answer:

$25%$ %

Step-by-step explanation:

Given: Jocelyn calculates that see will take 105 minutes to run 7 miles. She runs the distance in 84 minutes.

To find: Jillian’s percent error

Solution:

Actual time taken by Jocelyn to run 7 miles = 84 minutes

Approximate time taken by Jocelyn to run 7 miles = 105 minutes

Error = $|105-84|=21$ minutes

Percent error = error/(Actual time taken) × (100) = $\frac{21}{84}(100)=25\%$

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3 years ago

Which scatterplot does NOT suggest a linear relationship between x and y?

Misha Larkins [42]

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because a linear relationship is like a straight line going up or down (but not horizontal)

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3 years ago

Read 2 more answers

at 1:30 in the afternoon an old freight train and a new dart express train pull out of the new garland station going in opposite

zalisa [80]

Answer:

$V_{E} = -22.5 / 15 = 1.5 miles/minute\\V_{F} = 7.5 / 15 = 0.5 miles/minute$

Step-by-step explanation:

To answer this problem, we must bear in mind that the express train travels 3 times faster than the freight train.

If we call F the distance that the freight train travels and we call E at the distance that the express train travels, we must have the distance between them after 15 minutes it must be 30 miles.

$F + E = 30\\$