What is the sum of the first 40 odd integers greater than zero?
1 answer:
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Answer:
see below
Step-by-step explanation:
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1. To solve this we are going to use the formula for the area of a sector of a circle: 
where
is the area of the sector
is the radius of the circle
is the angle in radians
We know from our problem that the radius of the circle is 5 cm and the angle of the sector is
, so 
and 
. Lets replace those values in our formula:
We can conclude that the area of sector GHJ in terms of pi is
, and as a decimal rounded to the nearest tenth is 9.8 .
2. To c<span>onstruct the circle that circumscribes triangle DEF, we are going to draw the perpendicular bisectors of triangle DEF, and then we are going to draw the circle with radius at the interception point of the bisectors. Remember that the perpendicular bisector are the lines that passes trough the midpoint of the segment and are perpendicular to the segment.</span>
where
We know from our problem that the radius of the circle is 5 cm and the angle of the sector is
We can conclude that the area of sector GHJ in terms of pi is
2. To c<span>onstruct the circle that circumscribes triangle DEF, we are going to draw the perpendicular bisectors of triangle DEF, and then we are going to draw the circle with radius at the interception point of the bisectors. Remember that the perpendicular bisector are the lines that passes trough the midpoint of the segment and are perpendicular to the segment.</span>