Answer:
Normally it would be 40 and anything over 80 hours in a two-week time frame would be considered OT
Step-by-step explanation:
Answer:
idk, but depending on that juice i bet they are drunker then hail
Step-by-step explanation:
Step-by-step explanation and answer:
For this you just need to plug in x for y = f(1/5x)
1/5(-4) = -4/5 or -0.8
1/5(-1) = -1/5 or -0.2
1/5(0) = 0
1/5(3) = 3/5 or 0.6
1/5(6) = 6/5 or 1.2 or 1 1/5
Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
