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Len [333]
4 years ago
10

Which of the following is an arithmetic sequence? a.2,4,16,32 b.2,3,7,1, c.3,0,-3,-6 d.5,-5,5,-5

Mathematics
2 answers:
Lelechka [254]4 years ago
8 0

D. 5,-5,5,-5

because the others don't follow a constant pattern

Natali [406]4 years ago
8 0

Answer:

c apex im positive

Step-by-step explanation:

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In a high school football stadium, there are 3,892 seats. The stadium has 14 sections. Each section has the same number of seats
Nastasia [14]

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278, pls brainliest

Step-by-step explanation:

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3 years ago
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Asap?
vladimir2022 [97]

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the 2nd one lol

Step-by-step explanation:

8 0
3 years ago
Felicia has 35 quarters, 25 dimes, and 36 pennies. How many coins does Felicia have
koban [17]
Felicia has 96 coins because 30+20+30= 80.And 80+6=86. 86+10=96.
I hope I helped! :)
5 0
3 years ago
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Identify the expression for calculating the mean of a binomial distribution
TEA [102]

Option C: np is the expression used for calculating the mean of a binomial distribution.

Explanation:

From the options, we need to determine the expression that is used for calculating the mean of a binomial distribution.

<u>Option A: npq</u>

The variance of the binomial distribution can be calculated using the expression npq.

Hence, Option A is not the correct answer.

<u>Option B: </u>\sqrt{npq}<u></u>

The standard deviation of the binomial distribution can be calculated using the expression \sqrt{npq}

Hence, Option B is not the correct answer.

<u>Option C: np</u>

The mean of the binomial distribution can be calculated using the expression np

Hence, Option C is the correct answer.

<u>Option D</u>: \sum\left[x^{2} \cdot P(x)\right]-\mu^{2}

The mean of the binomial distribution cannot be determined using the expression \sum\left[x^{2} \cdot P(x)\right]-\mu^{2}

Hence, Option D is not the correct answer.

8 0
4 years ago
A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of m
nignag [31]

Answer:

Confidence Interval: (0.44,1.00)

Step-by-step explanation:

We are given the following data set:

0.60, 0.74, 0.09, 0.89, 1.31, 0.51, 0.94

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{:5.08}{7} = 0.725

Sum of squares of differences = 0.8809

S.D = \sqrt{\frac{0.8809}{6}} = 0.383

90% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 6 and}~\alpha_{0.10} = \pm 1.943  

0.725 \pm 1.943(\frac{0.383}{\sqrt{7}} ) =0.725 \pm 0.2812 = (0.44,1.00)

No, it does not appear that there is too much mercury in tuna​ sushi.

5 0
4 years ago
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