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Mnenie [13.5K]
3 years ago
13

What is the ZERO for the graph?

Mathematics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

that is the orgin which means the middle.

Step-by-step explanation:

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30% in simplest form
Lady bird [3.3K]

Answer:

I think it's 3/10

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
8. Find m Using the parallelogram
Semmy [17]

Answer:

w = 80

Step-by-step explanation:

Common geometry math

7 0
3 years ago
Could you please help me plzz I want to past my exam plzzzz
lorasvet [3.4K]
Pretty sure it’s D but if it is not then I don’t know
3 0
2 years ago
Please help me with these two questions!! show work too!
const2013 [10]

Answer:

x 37 y 30

Step-by-step explanation:

hopes it helps yo

4 0
3 years ago
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