Answer:
X = 7.24 or 7.2
Step-by-step explanation:
Tan46/1 = x/7
Cross multiply to get this outcome:
7tan(46)
Put into calculator
Then your answer will be X = 7.24 or 7.2
Hope that helps :)
Answer:
x = 30°.
Step-by-step explanation:
To calculate the value of 'x', we can first derive the value of one of the angles that make up the triangle.
Notice that there is an angle with a measure of 100°. The angle that makes up the angle of the triangle is called a Vertical Angle. Therefore, if the angle in red is 100°, the vertical angle, or the third angle of the triangle, is 100°.
There are two congruent sides to the triangle, as seen by the congruent lines. This means that both of the other two angles must be equal. Find the value of 'x' by:
180 - 100 = 80. Since the value of one angle was 100°, and the angles in a triangle must add up to 180°, you can simply subtract to find the sum of the other two angles.
(x + 10) + (x + 10) = 80
2x + 20 = 80
2x = 60
x = 30°.
A = -2
b = 4
c = -3
They are the coefficients to the terms in the equation<span />
Answer:


Step-by-step explanation:
The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.
Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:
Finding e:


hyp = 26
opp = e = ?
Plug in the values into the formula

Multiply both sides by 26





Since side e is of the same length with side f, therefore, the length of side f = 
Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.