Ask question

Ask question

All categories

andreev551 [17]

2 years ago

9

Yesterday Jefferson slept for 7 hours and 45 minutes. Katherine slept for 8 hours and 25 minutes. How much longer did Katherine

sleep than Jefferson?

1 answer:

xxTIMURxx [149]2 years ago

6 0

8 hours and 75 minutes later at the park and then I’ll be home Jefferson

You might be interested in

PLEASE HELP<br> I have no idea how to do this

tresset_1 [31]

Answer:

1st 2nd or both's answer you want

7 0

2 years ago

A group of 2 adults and 4 children spent $38 on tickets to a museum. A group of 3 adults and 3 children spent $40.50 on tickets

Paraphin [41]

Answer:

Divide the 1st equation by 2

a + 2c = 19

Divide the 2nd equation by 3

a + c = 13.5

Subtract the 1st equation and the 2nd equation

c = 5.5

Substituting back into the 2nd equation will give:

a + 5.5 = 13.5

a = 8

Step-by-step explanation:

8 0

3 years ago

Mr. Cole is putting hardwood flooring in the area of his house shown at the Wright. He is also putting crown molding around the

Leokris [45]

Answer:

are there any numbers?

Step-by-step explanation:

6 0

2 years ago

What is the slope between<br> the points (0,-3) and (-6,7)?

IceJOKER [234]

Answer:

-5/3

Step-by-step explanation:

8 0

2 years ago

What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu

inn [45]

Answer:

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Step-by-step explanation:

The given expression is

$\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}$

First, we need to factor each denominator

$\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}$

So, the least common factor (LCF) is $x(x-3)(x+3)$ , because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

$\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}$

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

Therefore, the expression is equivalent to

$\frac{(x+5)(x+2)}{x(x-3)(x+3)}$

8 0

2 years ago

Read 2 more answers