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3 years ago

Solve this equation: -9 -6 12h 40=22

Mathematics

2 answers:

abruzzese [7]3 years ago

7 0

Input
-9-6(12 h) times 40= 22

result

-2880h -9 =2

ikadub [295]3 years ago

5 0

Answer:

The equation seems to be something like:

-9 - 6*12h/40 = 22

but some of the signs are missing, i will try to give a some what general way of solivng these equations.

we want to solve it for h.

the first step is isolating h in one side of the equation, for this, we start adding 9 in both sides to remove the term that is not acting directly on h:

(-9 - 6*12h*40) + 9 = 22 + 9

- 6*12h*40 = 31

Now, we need to pass the terms that are acting directly on h, first we solve everithing we can:

-6*12*h/40 = -(6*12)*h/40 = -50/40*h = (-5/4)*h = 31

Now we divide in both sides by the number that is multiplicating h, so we can remove it:

(-5/4)/(-5/4)*h = h = 27/(-5/4) = (-27*4)/5 = -24.8

so for this particular equation, h = -24.8, but if the equation is different, you can do a similar proces to find the value og h.

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Your answer is 4/6 of the walls in the room.

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3 years ago

Convert 8π9/9

Zolol [24]

Answer:

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Step-by-step explanation:

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3 years ago

Find a1, for the arithmetic series with S14 = - 420 and d = -6.

faust18 [17]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} n = 14\\ d= -6 \end{cases} \\\\\\ a_{14}=a_1+(14-1)(-6)\implies a_{14}=a_1+(13)(-6)\implies a_{14}=a_1-78 \\\\[-0.35em] ~\dotfill$

$\bf \textit{sum of a finite arithmetic sequence} \\\\ S_n=\cfrac{n(a_1+a_n)}{2}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{last term's}\\ \qquad position\\ a_1=\textit{first term}\\ \cline{1-1} n= 14\\ S_{14}=-420\\ a_{14}=a_1-78 \end{cases}\implies S_{14}=\cfrac{n(a_1+a_{14})}{2} \\\\\\ -420=\cfrac{14[a_1+(a_1-78)]}{2}\implies -420=7(2a_1-78)\implies \cfrac{-420}{7}=2a_1-78 \\\\\\ -60=2a_1-78\implies 18=2a_1\implies \cfrac{18}{2}=a_1\implies 9=a_1$

8 0

3 years ago

the sum of three numbers is twenty. the second number is four times the first and the sum of the first and third is eight. what

8090 [49]

Let's call the three numbers x, y, and z.

The numbers are 3, 12, and 5.
x + y + z = 20
y = 4x
x + z = 8
We can rewrite the first equation because y is 4x, so
x + 4x + z = 20
5x + z = 20
And now we can use simultaneous equation rules to solve

5x + z = 20
x + z = 8

5x + z = 20
5x + 5z = 40
(subtract)
-4z + -20
÷ -4
z = 5

x + z = 8
x + 5 = 8
x = 3

y = 4x
y = 4 × 3
y = 12

I hope this helps!

4 0

3 years ago

2 points

miskamm [114]

The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3>Solution:</h3>

Given equation is 5x - 3y = 15

To find: x - intercept and y -intercept

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

Finding x - intercept:

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

Finding y - intercept:

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

y = -5

So the y - intercept is (0, -5)

5 0

3 years ago