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frozen [14]
3 years ago
6

95% of students at school weigh between 62 kg and 90 kg. Assuming this data is normally distributed, what are the mean and stand

ard deviation?
Mathematics
2 answers:
IceJOKER [234]3 years ago
7 0

Answer:

Mean is 76 and standard deviation is 7.

Step-by-step explanation:

Let \mu be the mean and \sigma is the standard deviation of the given data,

Thus, 95% of the data lies between \mu-2\sigma and \mu+2\sigma

Now, 95% of students at school weigh between 62 kg and 90 kg,

So, the mean is,

\mu=\frac{62+90}{2}=\frac{152}{2}=76

\implies 76+2\sigma = 90

2\sigma = 14

\implies \sigma = 7

stiks02 [169]3 years ago
5 0
We can calculate (62 + 90) / 2 = 76. it's <span>known that 95% lies between the mean and twice the standard deviation. </span><span>if the mean is "μ" and the standard deviation is "σ": </span><span>μ-2σ and μ+2σ. i</span><span>f μ=76, then </span><span>76+2σ = 90, so 2σ = 14, so σ = 7.
</span>
<span>the mean is 76 and the standard deviation 7. </span>
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A beekeeper has 65,000 female bees and 700 male bees in one colony. A disease kills % of the female bees and % of the male bees.
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Complete Question

A beekeeper has 65,000 female bees and 700 male bees in one colony. A disease kills 25% of the female bees and 14% of the male bees. After the disease hits the colony, the beekeeper decides to sell LaTeX: \frac{1}{2} 1 /2 of the remaining female bees to a friend.

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Step-by-step explanation:

From the above question:

Number of female bees = 65,000

Number of male bees = 700

A disease kills 25% of the female bees and 14% of the male bees.

Number of female bees killed = 25% × 65,000

= 16,250 bees

Amount of female bees left = 65,000 - 16,250

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Number of male bees killed = 14% × 700

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