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dsp73
3 years ago
11

Sorry had to repost lol could you answer part b of the question for me please???

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

hey one point goes through (-1.5,0) and( 0,3)

Step-by-step explanation:

Hope this helps

pls put brainliest

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Your English teacher has given you a list of 10 possible topics for essays. You need to pick four topics from the list to write
-Dominant- [34]
10-12 i think, because 10*4=40 and 12*4=48

8 0
3 years ago
A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
HELP PLEASE ASAP!!!!
vodomira [7]

Answer:

I may be wrong, but I learned that the first slot would be "terms". 4:3 would be an example of a ratio so it couldn't be ratio and a difference is subtracting.

The second slot would not be a geometric sequence because it is not correctly placed on the number line.

Therefore, the answers would be "terms" and "is not"

5 0
3 years ago
What conjecture can you make about the sum of the first 22 positive even numbers?
alekssr [168]

Answer:

A.) The sum of the product of the number of terms and the number of terms plus one.

Step-by-step explanation:

So, we have the sum of the first 22 positive even numbers:

S = 2 + 4+ 6 + ... + 44

We know the sum of such sequence is given by the (sum of the first number (2) and the last number (44)) multiplied by the number of terms (11).

S = (2 + 44) * 11 = 46 * 11 = 506

Answer A tells us it should be the sum of the number of terms (22) by the number of terms plus one (22 + 1 = 23).

S = 22 * 23 = 506

That's confirmed.

Answer B would give 22 * 21 = 462, so it's not right

Answer C would give 22 * 2 = 44, obviously not right

Answer D would give 22 * 22 = 484, close but not right.

7 0
3 years ago
Which expression is equivalent to: (x +9)(x+3)
labwork [276]

Answer:

c

Step-by-step explanation:

x*x=x^2

x*9=9x

x*3=3x

9x+3x=12x

9x3=27

x^2+12x+27

6 0
3 years ago
Read 2 more answers
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