Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Answer:
(4, 3 ) and (4, - 3 )
Step-by-step explanation:
A distance of 5 units from the origin represents the hypotenuse of a right triangle with sides 3- 4 - 5
If the x-coordinate is 4 then the y-coordinate is | 3 | = ± 3
the coordinates are (4, 3 ) and (4, - 3 )
Answer:
the answers are options 1, 2, and 5.
Step-by-step explanation:
2*5*9*x = 540
x = 540/90 = 54/9 = 6
option D
A. I think the cordinate of the meeting place will be 11,11 and for B I don't even know why that's there..
C. I think it's 11 too. Idk but, when you check ur homework you can ask ur teacher/parent for help.