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s344n2d4d5 [400]
3 years ago
10

Julio joined an athletic club. There was a one-time fee of $49.95 to join the club, plus a monthly fee of $24.95. Julio has paid

$424.20 to be in the club for m months. Write an equation that could be used to determine how many months Julio has been in the athletic club.
Mathematics
1 answer:
Rama09 [41]3 years ago
3 0

c (cost)
m (month)


c= xm + b

$424.20= 24.95m+ $49.95

Move everything except variable on one side.

424.20 - 49.95 = $374.24

$374.25 = 24.95m

Divide by 24.95

m = 15

15 Months
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Answer:

Collin: about $401 thousand

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Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

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In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

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In Cameron's case, we have ...

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Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

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If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

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k = ln(2)/15 ≈ 0.046210

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and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

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