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ira [324]
2 years ago
15

A)12/35 B)37/35 C)12/37 D)35/12 Please help

Mathematics
1 answer:
Licemer1 [7]2 years ago
8 0
It's 12/35 because tangent is opposite over adjacent, so 12 is opposite of angle M and 35 is adjacent of angle M

If you want to remember cosine, sine, and tangent just remember
SOH CAH TOA
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Given f(x) = 1/3(4 – x)^2 ,<br> what is the value of f(16)?
gayaneshka [121]

Answer:

48

Step-by-step explanation:

Plug in 16 to the function:

f(16)=1/3(4-16)^2

=1/3(-12)^2

=144(1/3)

=48

4 0
2 years ago
How do i do this: 5. graph f(x)=|x-1| and g(x)=|1/2x-1| Compare the graph of g to the graph of f 6. graph f(x)=|x+2|+2 and g(x)=
kari74 [83]
To graph <span>f(x)=|x-1| and g(x)=|1/2x-1|  pick some numbers for x and insert them into the equation for x. After inserting the numbers for x, solve and find f(x) and g(x)
For instance,  am going to insert 1 for f(x) and g(x)

</span><span>f(x)=|x-1| and g(x)=|1/2x-1| 

</span><span>f(1)=|1-1| and     g(1)=|1/2(1)-1| 
</span><span>f(1)= 0     and     g(1)=|1/2x-1| 

(1,0)        and      (1, -1/2)

After working the equation above we got our first point, which you can plot. Do the same to get the rest of your points to plot

</span>
7 0
3 years ago
A factory makes
Digiron [165]

Answer:

Each machine would produce 28,750 candies per day. hope it helps

3 0
2 years ago
Function A is a quadratic function with a vertex at (3, 4) and a leading coefficient of -1 Function B has the equation y = |x +
skad [1K]

With the information given, we deduce that the parabola is

y=-(x-3)^2+4 = -(x^2-6x+9)+4 = -x^2+6x-5

Reflecting a function over the x axis means to change its sign. After the reflection, the parabola becomes

y=x^2-6x+5

And to shift down a function, you subtract the shift from the equation: the equation becomes

y=x^2-6x+5-2=x^2-6x+3

Similarly, the other function is reflected over the x axis (sign change) and shifted up 3 (add 3 to the equation):

|x+2|\mapsto -|x+2|\mapsto -|x+2|+3

In order to compute the y intercept, we simply have to evaluate the functions at x=0: for the parabola we have

y(0)=3

For the other function, we have

y(0)=-|2|+3=-2+3=1

8 0
3 years ago
please help. i stayed up all night finishing this schoolwork i need help pleaseee please omg im begging someone to help me
ad-work [718]

Answer: Choice D) x = a\left(1-\frac{y}{b}\right)

================================================

Work Shown:

\frac{x}{a}+\frac{y}{b} = 1\\\\\frac{x}{a} = 1-\frac{y}{b}\\\\x = a\left(1-\frac{y}{b}\right)\\\\

Explanation:

First I subtracted y/b from both sides. Then I multiplied both sides by 'a' to fully isolate x. You can optionally distribute the 'a' through to each term inside the parenthesis, but your teacher has chosen not to do this.

5 0
2 years ago
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