Question

What is logs(4.7)+logs 2 written as a single log?

Answer 1

ANSWER

$log_{s}(56)$

EXPLANATION

The given logarithmic expression is:

$log_{s}(4 \times 7) + log_{s}(2)$

Recall and use the product rule of logarithm

$log_{a}(b) + log_{a}(c) = log_{s}(bc)$

We apply this rule to obtain,

$log_{s}(4 \times 7) + log_{s}(2) = log_{s}(4 \times 7 \times 2)$

We multiply out the argument to get;

$log_{s}(4 \times 7) + log_{s}(2) = log_{s}(56)$

The correct answer is

$log_{s}(56)$